SOLUTION: Dylan bought 80 kg of durians. 2/5 of it was rotten and was thrown away. He packed the remaining durians into packets of 2/3 kg each. How many packets of durians did he have?

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: Dylan bought 80 kg of durians. 2/5 of it was rotten and was thrown away. He packed the remaining durians into packets of 2/3 kg each. How many packets of durians did he have?      Log On


   

Question 1207263: Dylan bought 80 kg of durians. 2/5 of it was rotten and was thrown away. He packed the remaining durians into packets of 2/3 kg each. How many packets of durians did he have?
Found 2 solutions by ikleyn, math_tutor2020:
Answer by ikleyn(52790) About Me  (Show Source):
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2/5 of 80 kg is 2*16 = 32 kg.


They are thrown away.  The rest is 80 - 32 = 48 kg.


48%2F%28%282%2F3%29%29 = %2848%2A3%29%2F2 = 24*3 = 72 packets of 2/3 kg each.    ANSWER

Solved.



Answer by math_tutor2020(3817) About Me  (Show Source):
You can put this solution on YOUR website!

Answer: 72

Work Shown

2/5 of the batch is rotten, so the remaining 3/5 of the batch is still good.
The two fractions add to 5/5 aka 1. Draw a fraction diagram if needed.

3/5 of 80 = (3/5)*80 = 48 kg of durians are still good.

n = number of packets
(2/3)n = total weight since each packet weighs 2/3 kg
(2/3)n = 48
2n = 3*48
n = 3*48/2
n = 72 is the answer we want.