SOLUTION: A westbound float plane left Anchorage at 1:00 pm. Two hours later, an eastbound float plane left the same airport. The eastbound plane flew 30 mph faster than the westbound plane.

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Question 1207189: A westbound float plane left Anchorage at 1:00 pm. Two hours later, an eastbound float plane left the same airport. The eastbound plane flew 30 mph faster than the westbound plane. Find the rate of each plane if they were 600 miles apart at 5:00 pm.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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A westbound float plane left Anchorage at 1:00 pm.
Two hours later, an eastbound float plane left the same airport.
The eastbound plane flew 30 mph faster than the westbound plane.
Find the rate of each plane if they were 600 miles apart at 5:00 pm.
:
let s = speed of the slower plane (westbound)
then
s+30 = speed of the faster plane (eastbound)
:
4 hrs is the travel time of the slower plane
2 hrs is the time of the faster plane (two hours later)
:
total dist that both planes traveled is 600 mi
A dist equation
4s + 2(s+30) = 600
4s + 2s + 60 = 600
6s = 600 - 60
6s = 540
s = 540/6
s = 90 mph speed of the slower westbound plane
then
90 + 30 = 120 mph is the speed of the faster eastbound plane