SOLUTION: The bearing from City A to City B is Upper N 41 degrees Upper E. The bearing from City B to City C is Upper S 49 degrees Upper E. An automobile driven at 65 mph takes 1.4 hours to

Algebra ->  Trigonometry-basics -> SOLUTION: The bearing from City A to City B is Upper N 41 degrees Upper E. The bearing from City B to City C is Upper S 49 degrees Upper E. An automobile driven at 65 mph takes 1.4 hours to       Log On


   



Question 1207186: The bearing from City A to City B is Upper N 41 degrees Upper E. The bearing from City B to City C is Upper S 49 degrees Upper E. An automobile driven at 65 mph takes 1.4 hours to drive from City A to City B and takes 1.6 hours to drive from City B to City C. Find the distance from City A to City C.​ (Neglect the curvature of the​ earth.)

Answer by mananth(16946) About Me  (Show Source):
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The bearing from City A to City B is Upper N 41 degrees Upper E. The bearing from City B to City C is Upper S 49 degrees Upper E. An automobile driven at 65 mph takes 1.4 hours to drive from City A to City B and takes 1.6 hours to drive from City B to City C. Find the distance from City A to City C.​ (Neglect the curvature of the​ earth.)
From A to B
Distance
65*1.4 = 91 miles
From B to C
65*1.6 = 104 miles
Now the angle ABC (49+41)=90 deg by geometry (parallel lines and transversal)
AC^2 = AB^2 +BC^2
AC^2 = 91^2+104^2
AC = sqrt(91^2+104^2)