Question 120708:  what is the answer step by step to the following quadratic equations ? 
x squared-4x-15=0 
x squared+8x-33=0 
x squared+5x+2=0 
3xsquared-3x+6=0 
Help would be great i need it bad 
 Answer by jim_thompson5910(35256)      (Show Source): 
You can  put this solution on YOUR website! I'll do the first two to help you get started
 
#1
 
 
Let's use the quadratic formula to solve for x:
 
 
 
Starting with the general quadratic
 
 
 
 
 
the general solution using the quadratic equation is:
 
 
 
 
 
 
 
So lets solve   ( notice  ,  , and  )
 
 
 
 
 
  Plug in a=1, b=-4, and c=-15
 
 
 
 
  Negate -4 to get 4
 
 
 
 
  Square -4 to get 16  (note: remember when you square -4, you must square the negative as well. This is because  .)
 
 
 
 
  Multiply   to get  
 
 
 
 
  Combine like terms in the radicand (everything under the square root)
 
 
 
 
  Simplify the square root (note: If you need help with simplifying the square root, check out this  solver)
 
 
 
 
  Multiply 2 and 1 to get 2
 
 
So now the expression breaks down into two parts
 
 
  or  
 
 
 
Now break up the fraction
 
 
 
  or  
 
 
 
Simplify
 
 
 
  or  
 
 
 
So these expressions approximate to
 
 
  or  
 
 
 
So our solutions are:
 
  or  
 
 
Notice when we graph  , we get:
 
 
 
 
 
when we use the root finder feature on a calculator, we find that   and  .So this verifies our answer
 
 
 
 
 
 
 
#2
 
Let's use the quadratic formula to solve for x:
 
 
 
Starting with the general quadratic
 
 
 
 
 
the general solution using the quadratic equation is:
 
 
 
 
 
 
 
So lets solve   ( notice  ,  , and  )
 
 
 
 
 
  Plug in a=1, b=8, and c=-33
 
 
 
 
  Square 8 to get 64  
 
 
 
 
  Multiply   to get  
 
 
 
 
  Combine like terms in the radicand (everything under the square root)
 
 
 
 
  Simplify the square root (note: If you need help with simplifying the square root, check out this  solver)
 
 
 
 
  Multiply 2 and 1 to get 2
 
 
So now the expression breaks down into two parts
 
 
  or  
 
 
Lets look at the first part:
 
 
 
 
 
  Add the terms in the numerator
 
  Divide
 
 
So one answer is
 
 
 
 
 
 
Now lets look at the second part:
 
 
 
 
 
  Subtract the terms in the numerator
 
  Divide
 
 
So another answer is
 
 
 
 
So our solutions are:
 
  or  
 
 
Notice when we graph  , we get:
 
 
 
 
 
and we can see that the roots are   and  . This verifies our answer
 
 
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