Question 1207026: Mr. Daley bought some pigs, goats, and sheep. Altogether he bought 100 animals and spent 600 dollars. Mr. Daley paid 21 for each pig, 8 for each goat, and 3 for each sheep. There were an even number of pigs. How many of each animal did Mr. Daley buy?
Found 3 solutions by josgarithmetic, ikleyn, MathTherapy:
Answer by josgarithmetic(39621)   (Show Source):
Answer by ikleyn(52817)  (Show Source):
You can put this solution on YOUR website! .
There is nice solution under this link
https://nzmaths.co.nz/resource/pigs-goats-and-sheep
ANSWER. Mr Daley bought 10 pigs, 24 goats and 66 sheep.
Another solution is published under this link
https://www.quora.com/Mr-Daley-bought-some-pigs-goats-and-sheep-Altogether-he-bought-100-animals-and-spent-600-Mr-Daley-paid-21-for-each-pig-8-for-each-goat-and-3-for-each-sheep-There-was-an-even-number-of-pigs-How-many-of-each-animal
but it is WRONG.
Answer by MathTherapy(10555)  (Show Source):
You can put this solution on YOUR website!
Mr. Daley bought some pigs, goats, and sheep. Altogether he bought 100 animals and spent 600 dollars. Mr. Daley paid 21 for each pig, 8 for each goat, and 3 for each sheep. There were an even number of pigs. How many of each animal did Mr. Daley buy?
Let number of pigs and goats purchased, be P and G, respectively
Since 100 animals were purchased, number of sheep purchased, was 100 - (P + G) = 100 - P - G
Each pig, goat and sheep cost $21, $8, and $3, respectively
With him spending $600, total, we get the following equation: 21P + 8G + 3(100 - P - G) = 600
21P + 8G + 300 - 3P - 3G = 600
18P + 5G = 300
Now, since an even number of pigs were purchased, we need to solve the above equation, in 2 variables
(P and G), in terms of P (pigs). Therefore, 18P + 5G = 300 becomes: 
Looking at the above equation, solved for G, in terms of P, we see that P, in 18P, MUST be a MULTIPLE of 5, and
multiples of 5 are: 5, 10, 15, 20, and so on. However, it's stated that P (number of pigs) is an EVEN number.
Therefore, P MUST be 10, 20, 30, and so on. Trying 10, we get: 
With G being 24, and P being 10, number of sheep = 100 - P - G = 100 - 10 - 24 = 66.<===== This is 1 solution.
Trying the next EVEN INTEGER for the number of pigs, 20, gives us: 
Obviously, you CANNOT have a NEGATIVE number of animals, so, the only solution is what's stated
above. He purchased: _________________________
|Animal|# purchased|Cost|
|Pigs | 10|$210|
|Goats | 24|$192|
|Sheep | 66|$198|
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|Total | 100|$600|
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Of course, if NO pigs are purchased, then 60 goats and 40 sheep can be purchased
for $480 and $120, respectively. But again, it's stated that an EVEN number of
pigs were purchased, so this is CLEARLY NOT a solution.
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