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Question 1206989: A container with full capacity of 1l of water started leaking at a rate of 5 ml per second. At this rate, what fraction of the tank will still be filled with water after 2 minutes? Give your answer in the simplest form.
(1) 2/5
(2) 3/10
(3) 2/3
(4) 3/5
Found 4 solutions by math_tutor2020, ikleyn, josgarithmetic, MathLover1:
Answer by math_tutor2020(3817)   (Show Source):
You can put this solution on YOUR website!
Answer: 2/5
Explanation
The "1 l" looks a lot like two lowercase L's put together.
Perhaps your teacher should have written it as "1 L" or "one liter".
x = number of seconds that elapse
y = amount of water, in mL, in the tank
The equation is
y = -5x+1000
This is because the equation is of y = mx+b form
m = -5 = slope = how much water in mL leaks per second
b = 1000 = starting number of mL of water
1000 mL = 1 liter
If we plugged x = 0 into y = -5x+1000, then we'd get y = 1000.
Plug x = 120 into the equation to find that y = -5*(120)+1000 = 400
At the 2 minute marker, aka 120 seconds, 400 mL of water remains.
400/1000 = 2/5 of the tank is full by this point.
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Another approach
1 liter = 1000 mL
1 mL = 1/1000 = 0.001 liter
1 mL = 0.001 liter
5*1 mL = 5*0.001 liter
5 mL = 0.005 liter
The tank is losing 0.005 liters of water per second.
After 120 seconds (aka 2 minutes), the tank lost 120*0.005 = 0.6 liters of water.
The amount remaining is 1 liter - 0.6 liters = 0.4 liters
Divide this over the tank's capacity of 1 liter to get 0.4, note the "liters" units cancel when dividing.
Then convert that to a fraction
0.4 = 4/10 = 2/5
Answer by ikleyn(52866)  (Show Source):
Answer by josgarithmetic(39628) (Show Source):
You can put this solution on YOUR website! 1000 ml. filled at the start
Leak 5 ml. per second for 2 minutes;
or leak 5 ml. per second for 120 seconds.
 ml. still in the container.
The fraction remaining compared to at the start:
Answer by MathLover1(20850)  (Show Source):
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