SOLUTION: HOW OLD IS JANE? THE AGES OF JANE AND MARY WHEN ADDED TOGETHER MAKE 44 YEARS. JANE IS TWICE AS OLD AS MARY WAS WHEN JANE WAS HALF AS OLD AS MARY WILL BE WHEN MARY IS THREE TIMES

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Question 1206973: HOW OLD IS JANE?
THE AGES OF JANE AND MARY WHEN ADDED TOGETHER MAKE 44 YEARS. JANE IS TWICE AS OLD AS MARY WAS WHEN JANE WAS HALF AS OLD AS MARY WILL BE WHEN MARY IS THREE TIMES OLD AS JANE WAS WHEN JANE WAS THREE TIMES AS OLD AS MARY. HOW OLD IS JANE?
Found 2 solutions by ikleyn, greenestamps:
Answer by ikleyn(52781)   (Show Source):
You can put this solution on YOUR website!
.

https://math.stackexchange.com/questions/4453868/mary-m-is-twice-as-old-as-ann-a-was-when-m-was-half-as-old-as-a-will-be-when

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I agree with the comments of @greenestamps.

Regarding non-integral answer in the link, I'm not to blame for this.
All questions are not for me.

In this case my role is not teaching - only giving an information,
which I found in the Internet by spending my time to help you.

Regarding teaching, see similar problems solved in this lesson
    - Intricate age word problems

in this site.   It is really designed/intended to teach.

After reading it, you will be prepared enough to solve this type of age problems,
twisted enough, but not toooooo much, as in your post.

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Still ancient Greeks said that the main thing is a sense of proportion.
This feeling is obviously lost in this exercise.

Answer by greenestamps(13200)   (Show Source):
You can put this solution on YOUR website!

Just two comments about this problem....

(1) The purpose of a math problem should be to give students practice in math -- not practice in deciphering convoluted descriptions of the problem.

(2) In the solution cited by the other tutor, Mary's age turns out to be 27.5 years. Math problems involving ages can only have whole number answers.