SOLUTION: A bag contains 5 red balls and 3 blue balls. If two balls are drawn at random without replacement, what is the probability that both balls are red?

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Question 1206946: A bag contains 5 red balls and 3 blue balls. If two balls are drawn at random without replacement, what is the probability that both balls are red?
Found 2 solutions by ikleyn, greenestamps:
Answer by ikleyn(52756) About Me  (Show Source):
You can put this solution on YOUR website!
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This probability is     P = %285%2F8%29%2A%284%2F7%29 = 20%2F56 = 5%2F14 = 0.3571   (rounded).         ANSWER


In the formula,  first factor is the probability to get first ball red.

The second factor is the probability that the second ball is red,  given that the first ball is red.


Your intuition and/or your common sense should be consistent with this formal explanation.

In other words, based on your intuition, the formula above should seem to be obvious to you.



Answer by greenestamps(13196) About Me  (Show Source):
You can put this solution on YOUR website!


The response from the other tutor shows a solution using one standard method -- selecting the balls one at a time, finding the probability that each successive draw gets a red ball, and multiplying the two probabilities to get the final answer.

A student should know and understand that method for solving the problem.

The other basic method for solving the problem is using the basic definition of probability:
                    # of good outcomes
   probability = ------------------------
                  # of possible outcomes

A good outcome is choosing 2 of the 5 red balls; the number of ways of doing that is "5 choose 2": C(5,2)=10.

The possible outcomes are choosing any 2 of the 8 balls; the number of ways of doing that is "8 choose 2": C(8,2)=28.

So, using the basic definition of probability, the probability of choosing 2 red balls is 10/28 = 5/14.

ANSWER: 5/14