SOLUTION: A minimum value of a sinusoidal function is at (𝜋/4, 3). The nearest maximum value to the
right of this point is at (7𝜋/12, 7). Determine an equation of this function. Pleas
Algebra ->
Trigonometry-basics
-> SOLUTION: A minimum value of a sinusoidal function is at (𝜋/4, 3). The nearest maximum value to the
right of this point is at (7𝜋/12, 7). Determine an equation of this function. Pleas
Log On
Question 1206911: A minimum value of a sinusoidal function is at (𝜋/4, 3). The nearest maximum value to the
right of this point is at (7𝜋/12, 7). Determine an equation of this function. Please how all your wonderous work.
4. The pedals of a bicycle are mounted on a bracket whose centre is 25 cm above the ground. Each pedal is 14.5 cm from the centre of the bracket. Assuming that the bicycle is pedaled at 12 cycles per minute and that the pedal starts at t= 0s at the topmost position, determine both a sine and cosine function that gives the height, h, of point P above the ground at any time, 𝑡, where ℎ is in cm and
𝑡 is in seconds. Please also draw a labelled graph of one complete period for the function. Answer by ikleyn(52818) (Show Source):
You can put this solution on YOUR website! .
A minimum value of a sinusoidal function is at (𝜋/4, 3). The nearest maximum value to the
right of this point is at (7𝜋/12, 7). Determine an equation of this function. Please how all your wonderous work.
~~~~~~~~~~~~~~~~~~~~~~~~~
This sinusoidal function is between 3 and 7 on vertical axis, so the midline is
y= = 5 and the amplitude is 2 units.
The smallest distance between the minimum and the maximum is
- = - = = = .
along the horizontal axis. Hence, the period T is twice this value, i.e. T = .
Having the minimum at ((𝜋/4, 3), we can use negative cosine with the argument centered at 𝜋/4
y = = .
Solved.
---------------------
Post-solution note
Never pack more than one problem per post.
The rules of this forum (and the common sense) do not recommend make it.
Posting more than one problem per post, you work against your own interests.
No one forum for Math help does allow packing more than one problem per post
(which should be as clear as 2 x 2 = 4 to any homo sapiens).
