SOLUTION: In triangle PQR, AB//QR, If PA = 3x - 2, PB = 5x + 2, AQ = 5, BR = 10 and QR = 42, find:
x =
PA =
PB =
AB =
PQ =
Algebra ->
Triangles
-> SOLUTION: In triangle PQR, AB//QR, If PA = 3x - 2, PB = 5x + 2, AQ = 5, BR = 10 and QR = 42, find:
x =
PA =
PB =
AB =
PQ =
Log On
Question 1206817: In triangle PQR, AB//QR, If PA = 3x - 2, PB = 5x + 2, AQ = 5, BR = 10 and QR = 42, find:
x =
PA =
PB =
AB =
PQ = Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! Given AB ||PQ
Therefore triangles PQR and PAB are similar triangles ( by AA test)
THE RATIOS OF CORRESPONDING SIDES OF SIMILAR TRIANGLES ARE EQUAL.
PA+AQ=PQ
PB+BQ=PQ
PA/PQ = PB/PR
(3x-2 )/(3x+3) =(5x+2)/(5x+12)
(3x-2)(5x+12) = (3x+3)(5x+2)
3x(5x+12)-2(5x+12) = 3x(5x+2)+3(5x+2)
15x^2+36x -10x-24 =15x^2+6x+15x+6
26x-24 = 21x+6
5x=30
x=6
x = 6
PA =16
PB = 32
16/21= AB/42
16*42/21= 32
AB =32
PQ = 42
.
.
