SOLUTION: A loan of $ 10,000 is amortized by equal annual payments for 30 years at an effective annual interest rate of 8 %. Determine the year in which the interest portion of the payment i

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Question 1206656: A loan of $ 10,000 is amortized by equal annual payments for 30 years at an effective annual interest rate of 8 %. Determine the year in which the interest portion of the payment is most nearly equal to one-third of the payment.
The year that the interest portion of payment is most nearly equal to one-third of the payment =

Answer by ikleyn(52790) About Me  (Show Source):
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1206656
A loan of $ 10,000 is amortized by equal annual payments for 30 years
at an effective annual interest rate of 8 %. Determine the year in which
the interest portion of the payment is most nearly equal to one-third of the payment.
The year that the interest portion of payment is most nearly equal to one-third of the payment =
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

The solution is in three steps.  First, I determine the annual payment.
Then I determine a series of interest portion of the annual payments.
Then I look which of the interest portions is most nearly equal to one-third of the payment.


Use the formula for the annual payment for a loan

    Y = L%2A%28r%2F%281-%281%2Br%29%5E%28-n%29%29%29


where L is the loan amount; r = 0.08 is the annual interest rate;
n is the number of payments (in this problem it the same as the number of years); 
Y is the annual payment.


In this problem  P = $10,000;  r = 0.08,  n = 30 annual payments.


Substitute these values into the formula and get for monthly payment

    Y = 10000%2A%280.08%2F%281-%281%2B0.08%29%5E%28-30%29%29%29 = $888.27.


Thus, the annual payment is $888.27.


(1/3) of the annual payment is  888.27/3, or 296.09 dollars.


To determine the interest portions of annual payments, I use Excel function IPMT.


    For the description of this function, its parameters and syntaxis, see these sources

        wording/text description    
        https://www.wallstreetprep.com/knowledge/ipmt-function/

        Youtube videos
        https://www.youtube.com/watch?v=xZq4RNqE7ts
        https://www.youtube.com/watch?v=bni0l75lc-8



The table of results is shown below

Year        Interest part     the difference
            of the annual     between column 2
              payment         and 296.09 dollars
----------------------------------------------------
 1		800.00		503.91
 2		792.94		496.85
 3		785.31		489.22
 4		777.07		480.98
 5		768.18		472.09
 6		758.57		462.48
 7		748.19		452.10
 8		736.99		440.90
 9		724.88		428.79
10		711.81		415.72
11		697.70		401.61
12		682.45		386.36
13		665.98		369.89
14		648.20		352.11
15		629.00		332.91
16		608.25		312.16
17		585.85		289.76
18		561.66		265.57
19		535.53		239.44
20		507.31		211.22
21		476.83		180.74
22		443.92		147.83
23		408.37		112.28
24		369.97		 73.88
25		328.51		 32.42
26		283.73		 12.36    <<<---===
27		235.37		 60.72
28		183.13		112.96
29		126.72		169.37
30		 65.80		230.29


The minimum value in the third column is marked by  <<<---===.

It is 26-th year payment.


ANSWER.  The minimum difference is in the 26-th year payment.

Solved.