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Question 1206542: Austin made the hike to Mt. St. Helen's in 4 hours, and Snelling made the same hike in 5 hours. How far was the hike if Austin hiked 1 mph faster than Snelling?
Found 4 solutions by josgarithmetic, ikleyn, Edwin McCravy, greenestamps: Answer by josgarithmetic(39630) (Show Source): Answer by ikleyn(52898) (Show Source):
You can put this solution on YOUR website! .
Austin made the hike to Mt. St. Helen's in 4 hours, and Snelling made the same hike in 5 hours.
How far was the hike if Austin hiked 1 mph faster than Snelling?
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Let d be the one way distance, in miles.
Then the rate by Austin was miles per hour,
the rate by Snelling was miles per hours.
We are given that Austin traveled 1 mph faster than Snelling,
so we can write this equation
- = 1 mph.
At this point, the setup is complete.
To solve this equation, multiply both sides by 4*5 = 20, which is the common denominator.
You will get then
5d - 4d = 20,
d = 20.
So, one way distance is 20 miles. ANSWER
At this point, the solution is complete.
Answer by Edwin McCravy(20064) (Show Source): Answer by greenestamps(13214) (Show Source):
You can put this solution on YOUR website!
The formal algebraic solutions (or setups) shown by the other tutors are valid and useful.
But to learn how the problem can be solved informally almost immediately, you should be able to see that it makes sense that, because
(1) the distances are the same,
(2) the two times (4 hours and 5 hours) differ by 1 hour, and
(3) the two speeds differ by 1 mph
it must be that the two speeds are 5 mph and 4 mph.
So the distance is 4 hours at 5mph = 20 miles or 5 hours at 4mph = 20 miles.
ANSWER: 20 miles
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