9 letters; of them "e" repeats twice and "n" repeats twice.
The number of distinguishable permutations (arrangements) is
= = 7*6*5*3*2 = 1260.
The number of favorable arrangements is 1.
The probability is .
Solved.
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The way on how the problem is worded in the post is a mathematical tragedy.
Consider to hire somebody, who is able to write Math professionally, to edit your compositions after you.