Question 1206509: If 2ˣ = 4^y = 8^z and 1/2x + 1/4y + 1/8z = 22/7, show that:
x = 7/16, y = 7/32 and z = 7/48
Answer by ikleyn(52848)   (Show Source):
You can put this solution on YOUR website! .
If 2ˣ = 4^y = 8^z and 1/2x + 1/4y + 1/8z = 22/7, show that
x = 7/16, y = 7/32 and z = 7/48
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From the given part  =  =  , we have
=  =  .
It gives us x = 2y = 3z, or y =  , z =  .
Now substitute it into equation
 +  +  =  .
You will get
+  +  = ,
or
+  +  = ,
 + + = ,
 = ,
 = ,
x =  =  .
Then y = =  , z = =  , QED.
Solved.
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