SOLUTION: 7 -letter "words" (including non-sense words) are formed using the following 9 letters I, L, O, P, Q, R, U, X, Z. How many such words are possible if the second letter must be a vo

Algebra ->  Probability-and-statistics -> SOLUTION: 7 -letter "words" (including non-sense words) are formed using the following 9 letters I, L, O, P, Q, R, U, X, Z. How many such words are possible if the second letter must be a vo      Log On


   



Question 1206423: 7 -letter "words" (including non-sense words) are formed using the following 9 letters I, L, O, P, Q, R, U, X, Z. How many such words are possible if the second letter must be a vowel (letters can be repeated).
Answer by ikleyn(52880) About Me  (Show Source):
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7 -letter "words" (including non-sense words) are formed using the following 9 letters
I, L, O, P, Q, R, U, X, Z. How many such words are possible if the second letter must be
a vowel (letters can be repeated).
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In any of 6 positions (all except the second), any of 9 letters can appear.


In the second position, only one of 3 vowels (I, O, U) can appear.


So, in total,  3%2A9%5E6 = 1594323  such "words" are possible.    ANSWER

Solved.