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A group of friends went out for lunch.
Three people ordered soup. Two people ordered sandwiches.
Each sandwich costs twice as much as a bowl of soup.
Three people ordered burgers.
Each burger costs three times as much as a bowl of soup.
The total cost for their lunch was less than $40.48.
What was the price of a bowl of soup?
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Let x be the price of a bowl of soup.
Then the price of a sandwich is 2x, and the price of a burger is 3x.
Write an inequality for the total cost
3x + 2*(2x) + 3*(3x) < 40.48 (as stated in the problem).
Simplify
3x + 4x + 9x < 40.48
16x < 40.48
x < 2.53.
ANSWER. The price of a bowl of soup was less than $2.53.
Solved.
A little clunky, but that's all what can be done here.
