SOLUTION: 42% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults. Find the probability that the number of U.S. adults who have very little confidenc

Algebra ->  Probability-and-statistics -> SOLUTION: 42% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults. Find the probability that the number of U.S. adults who have very little confidenc      Log On


   



Question 1206290: 42% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults. Find the probability that the number of U.S. adults who have very little confidence in newspapers is ​ (a) exactly​ five, (b) at least​ six, and​ (c) less than four.
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
This is a binomial distribution problem, you can use this calculator:
https://stattrek.com/online-calculator/binomial

(a) exactly​ five
given:
number of trials: n+=++10
number of success trial: x+=+5
probability of success on a single trial: p+=+0.42

P%28x=5%29=0.21617
(b) at least​ six
P%28x%3E=+6%29=0.2016

(c) less than four
P%28x%3C+4%29=0.33346