SOLUTION: A bag of M & M's has 6 red, 4 green, 8 blue and 7 yellow . What is the probability of randomly picking:
1. a yellow...7/25?
b. a blue or green
3. an orange...0/25?
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-> SOLUTION: A bag of M & M's has 6 red, 4 green, 8 blue and 7 yellow . What is the probability of randomly picking:
1. a yellow...7/25?
b. a blue or green
3. an orange...0/25?
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Question 1206281: A bag of M & M's has 6 red, 4 green, 8 blue and 7 yellow . What is the probability of randomly picking:
1. a yellow...7/25?
b. a blue or green
3. an orange...0/25?
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Your answers to problems 1 and 3 are both correct. Nice work.
The fraction 0/25 can be reduced to 0; but it might be helpful to keep the fraction un-reduced.
Problem 2.
There are 4 green and 8 blue
4+8 = 12 are of either color mentioned.
12/25 is the probability of getting either of those colors (but not both at the same time) when selecting 1 M&M.
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