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Question 1206124: Mr Ronan had 2/3 as many yellow floorball sticks as red floorball sticks in the PE storeroom. He took 40 yellow floorball sticks and 18 red floorball sticks for a lesson. He then had 2/9 as many yellow floorball sticks left in the storeroom as red floorball sticks left. How many floorball sticks were there in the PE storeroom before the lesson?
Found 2 solutions by ikleyn, greenestamps: Answer by ikleyn(52802) (Show Source):
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Mr Ronan had 2/3 as many yellow floorball sticks as red floorball sticks in the PE storeroom.
He took 40 yellow floorball sticks and 18 red floorball sticks for a lesson.
He then had 2/9 as many yellow floorball sticks left in the storeroom as red floorball sticks left.
How many floorball sticks were there in the PE storeroom before the lesson?
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Let x be the total number of the floorball sticks in the PE storeroom before the lesson,
and let y be the number of the yellow floorball sticks of them.
Then the number of red sticks in the storage room before the lesson was x-y.
From the given part, we have this proportion
yellow = , or y = .
Multiply both sides by 3 and simplify
3y = 2(x-y), ---> 3y = 2x - 2y, ---> 3y + 2y = 2x, ---> 5y = 2x, ---> y = .
Thus the number of yellow sticks in the storeroom before the lesson was , or 0.4x.
the number of red sticks in the storeroom before the lesson was (x-0.4x) = 0.6x.
After taking 40 yellow floorball sticks and 18 red floorball sticks from the storeroom,
we have this equation
0.4x-40 = .
Multiply both sides by 9, then simplify and find x
9*(0.4x-40) = 2*(0.6x-18)
3.6x - 360 = 1.2x - 36
3.6x - 1.2x = 360 - 36
2.4x = 324
x = 324/2.4 = 135.
ANSWER. The number of floorball sticks in the PE storeroom before the lesson was 135.
Solved.
Answer by greenestamps(13200) (Show Source):
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