SOLUTION: You are flying a kite and have let out 80 m of string. The kite’s angle of elevation with the ground is 40°. If the string is stretched straight, how high is the kite above the

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Question 1206087: You are flying a kite and have let out 80 m of string. The kite’s angle of elevation with the ground is 40°. If the string is stretched straight, how high is the kite above the ground?

Found 2 solutions by ikleyn, MathLover1:
Answer by ikleyn(52802) About Me  (Show Source):
You can put this solution on YOUR website!
.

You have a right-angled triangle with the hypotenuse of 80 m long and one acute angle of 40°.

They ask about the opposite leg.

It is   80*sin(40°) = 80*0.6427876 = 51.423 m     (rounded).         ANSWER


                        Solved.



Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!


if you sketch it, you have right angle triangle where the length of the string is hypotenuse, the height is the opposite leg to the given angle of elevation
let angle be alpha=40°
hyp=80
sin%2840%29=h%2F80
h=80%2Asin%2840%29
h=51.4

answer: the kite is approximately 51.4 meters above the ground