SOLUTION: Find three consecutive even integers such that six times the sum of the first and the third is 8 less than 10 times the second?

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Question 1206054: Find three consecutive even integers such that six times the sum of the first and the third is 8 less than 10 times the second?
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

The three consecutive integers are x,+x+%2B+2, and x+%2B+4

if six times the sum of the first and the third is 8 less than 10 times the second, we have
6%28x+%2B+x+%2B+4%29=10%28x%2B2%29-8
6%282x+%2B+4%29=10%28x%2B2%29-8
12x+%2B+24=10x%2B20-8
12x+%2B+24=10x%2B12
12x+-10x+=12-24
2x+=-12
x=-6
than
x%2B2=-4
x%2B4=-2
three consecutive integers are: -2,-4,-6