SOLUTION: If 10% of cars approaching an intersection leg turn left, what is the probability that at least one out of three cars chosen at random will turn left?

Algebra ->  Probability-and-statistics -> SOLUTION: If 10% of cars approaching an intersection leg turn left, what is the probability that at least one out of three cars chosen at random will turn left?       Log On


   

Question 1206008: If 10% of cars approaching an intersection leg turn left, what is the probability that at least one out of three cars chosen at random will turn left?
Found 2 solutions by MathLover1, ikleyn:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

this is a binomial distribution
given:
n+=+3
p+=+0.10
the probability that at least one out of three:
P%281%3C=+x+%3C=3%29+
= 1+-+P%28x+=+0%29
= 1+-+0.9%5E3
= 1+-+0.7290
= 0.27


Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
.
If 10% of cars approaching an intersection leg turn left, what is the probability
that at least one out of three cars chosen at random will turn left?
~~~~~~~~~~~~~~~~~~~~ 

Then the probability that NO ONE of three cars will turn left is  0.9%5E3 = 0.729.


Respectively, the probability that at least one of three cars will turn left is the complement to it

    P = 1 - 0.9%5E3 = 1 - 0.729 = 0.271.    ANSWER

Solved.