SOLUTION: In a warehouse, 60% of the table lamps were 30 more than 80% of the standing lamps. Given that there were a total of 155 table and standing lamps in the warehouse at first, how man

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: In a warehouse, 60% of the table lamps were 30 more than 80% of the standing lamps. Given that there were a total of 155 table and standing lamps in the warehouse at first, how man      Log On


   

Question 1205965: In a warehouse, 60% of the table lamps were 30 more than 80% of the standing lamps. Given that there were a total of 155 table and standing lamps in the warehouse at first, how many table lamps were left if 30% of them were removed from the warehouse?
Found 2 solutions by josgarithmetic, MathLover1:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
t and s
table lamps and standing lamps

system%28%283%2F5%29t=30%2B%284%2F5%29s%2Ct%2Bs=155%29

system%283t=150%2B4s%2Ct%2Bs=155%29

system%283t-4s=150%2Ct%2Bs=155%29

system%283t-4s=150%2C3t%2B3s=465%29

subtract....
7s=315

highlight_green%28s=45%29
highlight_green%28t=110%29

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how many table lamps were left if 30% of them were removed from the warehouse?
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Question should not be troubling to solve.

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

the table lamps : x
the standing lamps: y
if 60% of the table lamps were 30 more than 80% of the standing lamps, we have
0.60x=0.80y%2B30....solve for x
x=0.80y%2F0.60%2B30%2F0.60
x=1.33333y+%2B+50.....eq.1

if there were a total of+155 table and standing lamps in the warehouse at first, we have

x%2By=155....eq.2, substitute x from eq.1
1.33333y+%2B+50%2By=155
2.33333y+=155-50
y+=105%2F2.33333
y=45

go to
x%2By=155....eq.2, substitute+y
x%2B45=155
x=155-45
x=110
there were 110+the table lamps
if 30% of them were removed from the warehouse, it will be
0.30%2A110=33+
so, 110-33=77 table lamps are left