SOLUTION: Why does the graph of the secant function have breaks in it?
A. Because the secant function is undefined at 𝝿.
B. Because the secant function is undefined at 𝝿 and - 𝝿
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-> SOLUTION: Why does the graph of the secant function have breaks in it?
A. Because the secant function is undefined at 𝝿.
B. Because the secant function is undefined at 𝝿 and - 𝝿
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Question 1205877: Why does the graph of the secant function have breaks in it?
A. Because the secant function is undefined at 𝝿.
B. Because the secant function is undefined at 𝝿 and - 𝝿.
C. Because the secant function is undefined at 0.
D. Because the secant function is undefined at 90° and -90°
E. Because the secant function has to reach infinity, which doesn't really exist.
F. Because the secant function has to have a break in it to be a function. Answer by MathLover1(20850) (Show Source):
You can put this solution on YOUR website!
The secant function was defined by the reciprocal identity
sec(x)=1/cos(x)
the secant function is when the cosine is , leading to vertical asymptotes at , , etc
° °
answer:
D. Because the secant function is undefined at ° and °