SOLUTION: Why does the graph of the secant function have breaks in it? A. Because the secant function is undefined at 𝝿. B. Because the secant function is undefined at 𝝿 and - 𝝿

Algebra ->  Trigonometry-basics -> SOLUTION: Why does the graph of the secant function have breaks in it? A. Because the secant function is undefined at 𝝿. B. Because the secant function is undefined at 𝝿 and - 𝝿      Log On


   

Question 1205877: Why does the graph of the secant function have breaks in it?
A. Because the secant function is undefined at 𝝿.
B. Because the secant function is undefined at 𝝿 and - 𝝿.
C. Because the secant function is undefined at 0.
D. Because the secant function is undefined at 90° and -90°
E. Because the secant function has to reach infinity, which doesn't really exist.
F. Because the secant function has to have a break in it to be a function.
Answer by MathLover1(20855) About Me  (Show Source):
You can put this solution on YOUR website!

The secant function was defined by the reciprocal identity
sec(x)=1/cos(x)
the secant function is undefined when the cosine is +0, leading to vertical asymptotes at pi%2F2, +3pi%2F2, etc

pi%2F2+=+90°
+3pi%2F2=-90°

answer:
D. Because the secant function is undefined at 90° and -90°