SOLUTION: Solve the following equations for all x, unless the domain is restricted. cos(1/2x) = 1/2 A. 2𝛑/3, + 2𝛑n B. 2𝛑/3 + 2𝛑n, 7𝛑/6 + 2𝛑n C. 7𝛑/6 D. no solut

Algebra ->  Trigonometry-basics -> SOLUTION: Solve the following equations for all x, unless the domain is restricted. cos(1/2x) = 1/2 A. 2𝛑/3, + 2𝛑n B. 2𝛑/3 + 2𝛑n, 7𝛑/6 + 2𝛑n C. 7𝛑/6 D. no solut      Log On


   



Question 1205835: Solve the following equations for all x, unless the domain is restricted.
cos(1/2x) = 1/2
A. 2𝛑/3, + 2𝛑n
B. 2𝛑/3 + 2𝛑n, 7𝛑/6 + 2𝛑n
C. 7𝛑/6
D. no solution
E. 3𝛑/4 + 2𝛑n
F. 𝛑/2

Found 2 solutions by Theo, ikleyn:
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
i believe tis can be solved as follows:

start with cos(1/2 * x) = 1/2

i'll work in degrees because it's easier.
you can then convert to radians by using the formula degrees = radians * 180 / pi.

solve for the angle by taking arcos(1/2) = 60 degrees.
that's in the first quadrant.
cosine is positive in the first and the fourth quadrant.

in the fourth quadrant, the equivalent angle is 360 - 60 = 300 degrees.

you get 1/2 * x = 60 degrees and 300 degrees.
using your calculator, you find that:
cos(60) = 1/2
cos(300) = 1/2

solving for x, you get x = 120 degrees and 600 degrees.

converting from degrees to radians, you get x = 120 * pi / 180 = 2/3 * pi and you get x = 600 * pi / 180 = 10/3 * pi.

x = 2/3 * pi and 10/3 * pi.

since the frequency is 1/2, then the period = 2pi / (1/2) = 4pi.

the cosine function will repeat every 4pi units forever going forward and backward.

consequently, your solution is x = 2/3 * pi plus or minus 4pi * n and 10/3 * pi plus or minus 4pi * n.

on a graph, it would look like this.



the equation for the graph is y = cos(1/2 * x)

i only showed 3 periods:
the period before
the base period
the period after

the solution is x = 2/3 * pi plus or minus 4pi * n and 10/3 * pi plus or minus 4pi * n.

in the base period you get x = 2pi/3 and 10pi/3

in the period before you get x = 2pi/3 - 12pi/3 = -10pi/3 and you get 10pi/3 - 12pi/3 = -2pi/3.

in the period after you get 2pi/3 + 12pi/3 = 14pi/3 and you get 10pi/3 + 12pi/3 = 22pi/3.

note that 12pi/3 is equal to 4pi so that plus or minus 4pi is the same as plus or minus 12pi/3.

unfortunately 2pi/3 and 10pi/3 are not in the solution set shown.

if the solution has to be one of the ones shown, then the solution would have to be selection D which should be re-labeled as solution not shown, because there is a solution but it's not shown.

Answer by ikleyn(52919) About Me  (Show Source):
You can put this solution on YOUR website!
.

Your starting equation is 

    cos(1/2x) = 1/2    (1)


Cosine is positive in QI and QIV.


Equation (1) has two sets of solutions.  One set is in QI

    %281%2F2%29x = pi%2F3+%2B+2%2Api%2An.    (2)


The other set of solutions is in QIV

    %281%2F2%29x = 5pi%2F3+%2B+2%2Api%2An.   (3)



Accordingly, we have two sets of solutions for x.  From (2), we have this set

    x = 2pi%2F3+%2B+4%2Api%2An.     (4)


From (3), we have this set

    x = 20pi%2F3+%2B+4%2Api%2An.    (5)


ANSWER. The solutions to the given equation are these two sets of angles

            x = 2pi%2F3+%2B+4%2Api%2An  and  x = 20pi%2F3+%2B+4%2Api%2An.

        These sets have no intersections.

Solved.

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No one of these (true) answer sets is presented in your answer list - - - so, your answer list is DEFECTIVE.