Question 1205742:  On some busy streets, diamond lanes are reserved for taxis, buses, and cars with three or more passengers. 
It is estimated that 20% of cars travelling in a certain diamond lane have fewer than three passengers. 
a. Is the variable in the question discrete or random? Justify your answer. 
If 60 cars that travel in a certain diamond lane are selected at random, find the probability that: 
b. exactly 10 cars have less than 3 passengers. 
 Answer by ikleyn(52903)      (Show Source): 
You can  put this solution on YOUR website! . 
On some busy streets, diamond lanes are reserved for taxis, buses, and cars  
with three or more passengers. It is estimated that 20% of cars travelling  
in a certain diamond lane have fewer than three passengers.  
If 60 cars that travel in a certain diamond lane are selected at random, find the probability that: 
exactly 10 cars have less than 3 passengers. 
~~~~~~~~~~~~~~~~~~~~~~~~~~~
 
 
Obviously, this problem is on the binomial distribution.
The number of trials is n= 60; the probability of the success (fever than 3 passengers) is p= 0.2.
The number of success trials k is k=10.
Since the number of trials, 60, is great, it is recommended to use the normal approximation to 
the binomial approximation.
In this normal approximation, the mean is mean = np = 60*0.2 = 12; the standard deviation
SD =   =   = 3.098386677.
In this problem, you should find a normal distribution probability to get k=10. 
We can use a regular hand calculator TI-83/84 with standard function normalcfd
                   z1   z2   mean    SD          <<<---===  formatting pattern 
    P = normalcfd(9.5, 10.5, 12,   3.098386677).                                  (1)
Here 9.5, 10.5 are the continuity correction factors to the number of 10.
The  ANSWER  (the value of (1)) is the probability  P = 0.1043  (rounded).
Alternatively, to find the value of (1), you may use the online calculator at web-site
https://onlinestatbook.com/2/calculators/normal_dist.html
It has very convenient simple interface, so even a beginner student can use it without further
explanations.  This calculator will produce the same answer (the same value of probability).
 
 
Solved.
 
 
 
 
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