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Question 1205615:  Sheik had some $2, $5 and $10 notes. The ratio of the number of $2 notes to the number of $5 notes to the number of $10 notes was 1:3:5. After spending 
all his $10 notes and 5/6 of his $5 notes, he had $783 left. How much money 
did he have at first? 
 Found 3 solutions by  math_tutor2020, josgarithmetic, greenestamps: Answer by math_tutor2020(3817)      (Show Source): 
You can  put this solution on YOUR website!  
Edit: I realize I made an error forming the equation. The error has been fixed.
 
 
x = number of $2 notes 
3x = number of $5 notes 
5x = number of $10 notes 
Since x is a number of something, it can only be a positive whole number {1,2,3,4,...}
 
 
The ratio x:3x:5x reduces to 1:3:5 after dividing all parts by the GCF x.
 
 
 
He spends all of his $10 notes, so we ignore the 5x portion. 
He spends 5/6 of his $5 notes and has 1/6 of those notes remaining.
 
 
2x = value of just the $2 notes 
5*(1/6)*3x = 5*0.5x = 2.5 = value of the remaining $5 notes
 
 
2x+2.5x = 4.5x = total value of all of his remaining money
 
 
4.5x = 783 
x = 783/(4.5) 
x = 174
 
 
Then, 
x = 174 = number of $2 notes 
3x = 3*174 = 522 = number of $5 notes 
5x = 5*174 = 870 = number of $10 notes
 
 
So, 
2*174 + 5*522 + 10*870 = 11658 
The total amount of money he started with is $11,658
 
 
Check: 
He spent all 870 of the $10 notes, so he has 11658 - 10*870 = 2958 dollars remaining. 
Then he spent 5/6 of the 522 copies of the $5 notes, meaning he spent 5*(5/6)*522 = 5*435 = 2175 further dollars. 
He is ultimately left with 2958 - 2175 = 783 dollars which confirms the answer is correct. 
 
 
 Answer by josgarithmetic(39630)      (Show Source):  Answer by greenestamps(13215)      (Show Source): 
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