SOLUTION: If you solve the question below, I'll be appreciated. A study on the length of time a person brushes their teeth is conducted on a large population of adults. The mean brushing

Algebra ->  Probability-and-statistics -> SOLUTION: If you solve the question below, I'll be appreciated. A study on the length of time a person brushes their teeth is conducted on a large population of adults. The mean brushing       Log On


   

Question 1205517: If you solve the question below, I'll be appreciated.
A study on the length of time a person brushes their teeth is conducted on a large population of adults. The mean brushing time is \mu and the standard deviation is \sigma. A simple random sample of 270 adults is considered.
(NOTE: For the following problems enter: '' GREATER THAN '', '' EQUAL TO '', '' LESS THAN '', or '' NOT ENOUGH INFORMATION '', without the quotes.)
(a) The mean of the sampling distribution is ? the mean of the population.
(b) The standard deviation of the sampling distribution is ? the standard deviation of the population.
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

A study on the length of time a person brushes their teeth is conducted on a large population of adults.
The mean brushing time is mu and the standard deviation is sigma.
A simple random sample of 270 adults is considered.
(a) The mean of the sampling distribution is equal+to+the mean of the population.
(b) The standard deviation of the sampling distribution is less+than the standard deviation of the population.
Explanation:
means are equal+to each other
standard deviation is always+less