SOLUTION: If 10,000 bacteria live in a test tube at 12pm and grow continuesly to 13000 at 3pm. Use the formula A= pe raised to rt, and find how many bacteria at 7pm. Where a is new populati

Algebra ->  Test -> SOLUTION: If 10,000 bacteria live in a test tube at 12pm and grow continuesly to 13000 at 3pm. Use the formula A= pe raised to rt, and find how many bacteria at 7pm. Where a is new populati      Log On


   



Question 1205447: If 10,000 bacteria live in a test tube at 12pm and grow continuesly to 13000 at 3pm. Use the formula A= pe raised to rt, and find how many bacteria at 7pm. Where a is new population of bacteria, p is initial population of bacteria, and r is the growth rate, and t is time in hrs.
Answer by greenestamps(13203) About Me  (Show Source):
You can put this solution on YOUR website!


A=pe%5E%28rt%29

From the given information about the numbers of bacteria at 12pm and 3pm....

13000=10000e%5E%283r%29
e%5E%283r%29=1.3

Using that to find the number of bacteria at 7pm....

x=10000e%5E%287r%29
x=10000%28e%5E%283r%29%29%5E%287%2F3%29
x=10000%281.3%29%5E%287%2F3%29
x = 18444.54 to 2 decimal places; round to the nearest whole number.

ANSWER: 18,445 bacteria at 7pm