SOLUTION: (2c^2-8)/(4c^2-8c) DIVIDED BY (c^3+2c^2)/(8c^3)

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Question 120541: (2c^2-8)/(4c^2-8c) DIVIDED BY (c^3+2c^2)/(8c^3)
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

%28%282c%5E2-8%29%2F%284c%5E2-8c%29%29%2F%28%28c%5E3%2B2c%5E2%29%2F%288c%5E3%29%29 Start with the given expression


%28%282c%5E2-8%29%2F%284c%5E2-8c%29%29%28%288c%5E3%29%2F%28c%5E3%2B2c%5E2%29%29 Multiply the first fraction by the reciprocal of the second fraction

%28%282%28c%2B2%29%28c-2%29%29%2F%284c%5E2-8c%29%29%28%288c%5E3%29%2F%28c%5E3%2B2c%5E2%29%29 Factor 2c%5E2-8 to get 2%28c%2B2%29%28c-2%29

Factor 4c%5E2-8c to get 4c%28c-2%29

Factor 8c%5E3 to get 8c%5E2%2Ac

Factor c%5E3%2B2c%5E2 to get c%5E2%28c%2B2%29


2%28c%2B2%29%28c-2%29%288c%5E2%2Ac%29%2F%284c%28c-2%29c%5E2%28c%2B2%29%29 Combine the fractions


Cancel like terms



%282%2A8c%29%2F%284c%29 Simplify



16c%2F%284c%29 Multiply



4 Divide



So %28%282c%5E2-8%29%2F%284c%5E2-8c%29%29%28%288c%5E3%29%2F%28c%5E3%2B2c%5E2%29%29 simplifies to 4



In other words, %28%282c%5E2-8%29%2F%284c%5E2-8c%29%29%28%288c%5E3%29%2F%28c%5E3%2B2c%5E2%29%29=4