SOLUTION: A movie theater has two ticket prices: $8.00 for adults and $5.00 for children. If the box office took in $4116 from the sale of 600 tickets, how many of each kind were sold?

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: A movie theater has two ticket prices: $8.00 for adults and $5.00 for children. If the box office took in $4116 from the sale of 600 tickets, how many of each kind were sold?      Log On


   

Question 120540This question is from textbook Mathematical ideas
: A movie theater has two ticket prices: $8.00 for adults and $5.00 for children. If the box office took in $4116 from the sale of 600 tickets, how many of each kind were sold? This question is from textbook Mathematical ideas

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Let's call the number of adult tickets, A, and the number of children's tickets, C.
1.A%2BC=600 The total number of tickets sold was 600.
2.4A%2B2C=1320 The total value of adult tickets ($8xA) children's tickets ($5xC) was $4116.
Use equation 1 to solve for A in terms of C.
1.A%2BC=600
A=600-C
Now substitute for A in equation 2 and solve for C.
2.8A%2B5C=4116
8%28600-C%29%2B5C=4116
4800-8C%2B5C=4116
-3C=-684
C=228
From 1,
A=600-C
A=600-228
A=372
372 Adult tickets sold and 228 children's tickets sold.