SOLUTION: Question content area top Part 1 How much must be deposited today into the following account in order to have 30,000 in 7 years for a down payment on a​ house? Assume no addit

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Question 1205267: Question content area top
Part 1
How much must be deposited today into the following account in order to have 30,000 in 7 years for a down payment on a​ house? Assume no additional deposits are made.
An account with quarterly compounding and an APR of 6.6 ​%
Question content area bottom
Part 1
​$
  
enter your response here should be deposited today.
​(Do not round until the final answer. Then round to the nearest cent as​ needed.)

Answer by ikleyn(52864) About Me  (Show Source):
You can put this solution on YOUR website!
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Question content area top
Part 1
How much must be deposited today into the following account in order to have 30,000 in 7 years for a down payment on a​ house? Assume no additional deposits are made.
An account with quarterly compounding and an APR of 6.6 ​%
Question content area bottom
Part 1
​$
  
enter your response here should be deposited today.
​(Do not round until the final answer. Then round to the nearest cent as​ needed.)
~~~~~~~~~~~~~~~~~~~

We have one time deposit "today". The amount of the deposit is x dollars (an unknown value).
The deposit is compounded quarterly at 6.6% annual interest.


The goal is to get $30000 in 7 years.


The formula for the future value at given conditions is


    30000 = x%2A%281%2B0.066%2F4%29%5E%287%2A4%29.


Here the number "4" is standing for 4 quarters per year.


From the equation,

    x = 30000%2F%281%2B0.066%2F4%29%5E28 = 18972.06  (rounded to the nearest cent).   ANSWER

Solved.

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Some people learn the subject better, when they see several similar solved problems,
collected in one place.

Keeping it in mind,  I provide here the references to my lessons in this site,
where several similar problems are placed.  The links are

    - Compounded interest percentage problems
    - Problems on discretely compound accounts

in this site.  Learn the subject from there.