SOLUTION: An urn contains 8 red chips, 10 green chips, and 2 white chips. A chip is drawn and replaced, and then a second chip drawn. What is the probability of (a) a white chip on the fi

Algebra ->  Probability-and-statistics -> SOLUTION: An urn contains 8 red chips, 10 green chips, and 2 white chips. A chip is drawn and replaced, and then a second chip drawn. What is the probability of (a) a white chip on the fi      Log On


   



Question 1205040: An urn contains 8 red chips, 10 green chips, and
2 white chips. A chip is drawn and replaced, and then a
second chip drawn. What is the probability of
(a) a white chip on the first draw?
(b) a white chip on the first draw and a red on the
second?
(c) two green chips being drawn?
(d) a red chip on the second given that a white chip
was drawn on the first?

Answer by ikleyn(52879) About Me  (Show Source):
You can put this solution on YOUR website!
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An urn contains 8 red chips, 10 green chips, and 2 white chips.
A chip is drawn and replaced, and then a second chip drawn.
What is the probability of
(a) a white chip on the first draw?
(b) a white chip on the first draw and a red on the second?
(c) two green chips being drawn?
(d) a red chip on the second given that a white chip was drawn on the first?
~~~~~~~~~~~~~~~~~~~~~~


The total number of balls is 8 + 10 + 2 = 20.
Since this experiment is with replacement, the situation after first draw and replacement
is the same as the starting situation.


(a)  P = 2%2F20 = 1%2F10 = 0.1 = 10%.    ANSWER


(b)  P = %282%2F20%29%2A%288%2F20%29 = 16%2F400 = 4%2F100 = 1%2F25 = 0.04 = 4%.    ANSWER


(c)  P = %2810%2F20%29%2A%2810%2F20%29 = 100%2F400 = 25%2F100 = 1%2F4 = 0.25 = 25%.    ANSWER


(d)  P = 8%2F20 = 40%2F100 = 2%2F5 = 0.4 = 40%, independently of the first draw.    ANSWER

Solved.

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