SOLUTION: There are three consecutive odd integers. The sum of quadruple the largest and twice the smallest is 46. What is the middle integer?

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Question 1205018: There are three consecutive odd integers. The sum of quadruple the largest and twice the smallest is 46. What is the middle integer?
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!


let’s three odd consecutive integers be x, x%2B2, and x%2B4
if the sum of quadruple the largest and twice the smallest is 46, we have
4%28x%2B4%29%2B2x=46...simplify, both sides divide by 2
2%28x%2B4%29%2Bx=23
2x%2B8%2Bx=23
3x=23-8
3x=15
x=5
integers are: 5,+7,9

check
4%28x%2B4%29%2B2x=46
4%289%29%2B2%2A5=46
36%2B10=46
46=46