You can put this solution on YOUR website! AC =DC given
BE =45
Let BC =x CE=45-x
AC^2= AB^2+BC^2
AC^2= 18^2+x^2 ( Pythagoras Theorem)
CD^2= CE^2+DE^2
CD^2 = (45-x)^2+20^2
AC =DC given
18^2+x^2=(45-x)^2+20^2
18^2+x^2= 45^2-90x+x^2+20^2
90x =45^2+20^2-18^2
90x=2101
x=23.344 cm =BC
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