SOLUTION: If 5 -letter words'' are formed using the letters A, B, C, D, E, F, G, how many such words are possible for each of the following conditions: (a) No condition is imposed. Your

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Question 1204819: If 5 -letter
words'' are formed using the letters A, B, C, D, E, F, G, how many such words are possible for each of the following conditions:
(a) No condition is imposed.
Your answer is :

(b) No letter can be repeated in a word.
Your answer is :
(c) Each word must begin with the letter A and letters can be repeated.
Your answer is :

(d) The second letter must be a vowel and no letters can be repeated.
Your answer is :

Found 3 solutions by MathLover1, math_tutor2020, ikleyn:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
If 5 -letter words are formed using the letters A, B, C, D, E, F, G, how many such words are possible for each of the following conditions:

(a) No condition is imposed.
There are 7 choices for the first letter.
There are 7 choices for the second letter
There are 7 choices for the third letter.
There are 7 choices for the fourth letter
There are 7 choices for the fifth letter.
The total number of 5-letter words possible:
7%2A+7+%2A+7+%2A7%2A7+=+16807
Your answer is : 16807

(b) No letter can be repeated in a word.
For the first letter, there are 7 choices.
For the second letter, there are only 6choices left (since we cannot repeat the first letter).
For the third letter there are 5 choices.
For the fourth letter there are 4 choices.
For the fifth letter there are 3+ choices.
The total number of 5-letter words possible with no letter repeated:
7+%2A+6%2A+5+%2A+4+%2A3=+2520
Your answer is : 2520


(c) Each word must begin with the letter A and letters can be repeated.
For the first letter, there is only 1 choice (the letter A).
For the second letter there are 7 choices (since any letter can be used).
For the third letter there are 7+choices, for the fourth letter there are 7+choices, and for the fifth letter there are 7 choices.
The total number of 5-letter words is possible with the first letter being A:
1+%2A+7+%2A+7+%2A7+%2A7=+2401
Your answer is : 2401

(d) The second letter must be a vowel and no letters can be repeated.
For the first letter, there are 7 choices (since any letter can be used).
For the second letter, there are 2 choices (the vowels A, and E).
For the third letter there are 5 choices, for the fourth letter there are 4 choices, and for the fifth letter there are 34 choices.
The total number of 5-letter words possible with the second letter being a vowel:
7+%2A2+%2A5+%2A4%2A3+=+840
Your answer is : 840


Answer by math_tutor2020(3817) About Me  (Show Source):
You can put this solution on YOUR website!

Answers:
(a) 16807
(b) 2520
(c) 2401
(d) 720


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Explanation for part (a)

There are 7 letters in the set {A,B,C,D,E,F,G}

When no condition is imposed, we can repeat letters.
There are 7 choices and 5 slots to fill. Giving 7^5 = 16807 different words possible.
Most of these "words" won't be found in the dictionary, but are simply strings of the letters mentioned.

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Explanation for part (b)

Unlike the previous part, we cannot repeat letters here.
There are 7 choices for the first slot, then 6 for the next slot, and so on.

We have 7*6*5*4*3 = 2520 different permutations possible.

Alternatively, use the nPr formula with n = 7 and r = 5.

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Explanation for part (c)

The first slot is locked to letter A.
The remaining 4 letters can be anything of the set {A,B,C,D,E,F,G} where repeats are allowed.
The logic is similar to part (a) we've done earlier.
We have 7^4 = 2401 different words that start with A when repeat letters are allowed.

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Explanation for part (d)

Given set = {A,B,C,D,E,F,G}
vowels from that set = {A, E}

There are 2 choices for the second slot (either A or E)
There are 7-1 = 6 choices for the first slot, due to one of the vowels already taken.
Then 6-1 = 5 choices for the third slot, 5-1 = 4 choices for the fourth slot, and 4-1 = 3 choices for the last slot.

6*2*5*4*3 = 720 permutations where a vowel is the second letter.

Answer by ikleyn(52787) About Me  (Show Source):
You can put this solution on YOUR website!
.

        For part  (d),  the solution and the answer in the post by  @MathLover1 are incorrect.

        The correct solution is as follows


2 options for the 2nd letter (A or E);

7-1 = 6 options for 1st letter;

5 options for 3rd positions;

4 options for 4th position;

3 options for last, 5th position.


In all,  2*6*5*4*3 = 720 different options are possible.   ANSWER for (d)