Question 1204807: A point (x, y) is randomly chosen in the square: -1 < x < 1, -2 < y < 0. What is the probability that the inequality x + y < 1 holds true?
Found 3 solutions by greenestamps, ikleyn, Edwin McCravy:
Answer by greenestamps(13203)   (Show Source):
You can put this solution on YOUR website!
The entire square lies below the graph of the given inequality....
ANSWER: 1 (or 100%)
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If you want to change the inequality, then re-post the new problem.
Answer by ikleyn(52824)  (Show Source):
You can put this solution on YOUR website! .
Draw a plot to make sure that this "open" square is entirely below the line y = 1-x,
without having common points with the line.
It tells you that if the point (x,y) is randomly chosen in the square,
then the probability is 1 (or 100%) that the inequality x + y < 1 is true.
ANSWER. The probability is equal to 1 (or 100%).
Solved.
Answer by Edwin McCravy(20060)  (Show Source):
You can put this solution on YOUR website!
Greenestamps is right because the inside of the square is below the line.
All the points are below the line.
[The line passes through the upper right corner of the square, but we
are not including points on the line or on the square, just inside (not 'on')
the square, and below (not 'on') the line.]
Edwin
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