SOLUTION: 2 ^ log(2,(2x + 3)) + 5^log(5,(x + 7)) = 7 ^ log_7(2x + 18)

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Question 1204786: 2 ^ log(2,(2x + 3)) + 5^log(5,(x + 7)) = 7 ^ log_7(2x + 18)
Found 2 solutions by MathLover1, Alan3354:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!




use log rule: b%5E%28log%28b%2Ck%29%29=k

2%5E%28log%282%2C%282x+%2B+3%29%29%29=2x+%2B+3
5%5E%28log%285%2C%28x+%2B+7%29%29%29=x+%2B+7
7%5E%28log%287%2C%282x+%2B+18%29%29%29=2x+%2B+18


2x+%2B+3%2Bx+%2B+7=2x+%2B+18
3x+%2B+10=2x+%2B+18
3x+-2x=++18-10
x=++8


Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
2 ^ log_2(2x + 3) + 5 ^ log_5(x + 7) = 7 ^ log_7(2x + 18)
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2x+3 + (x+7) = 2x+18
3x + 10 = 2x + 18
x = 8