SOLUTION: Two ships left a port at the same time. One ship traveled at a speed of 11 miles per hour at a heading of 320°. The other ship traveled at a speed of 25 miles per hour at a headin
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-> SOLUTION: Two ships left a port at the same time. One ship traveled at a speed of 11 miles per hour at a heading of 320°. The other ship traveled at a speed of 25 miles per hour at a headin
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Question 1204768: Two ships left a port at the same time. One ship traveled at a speed of 11 miles per hour at a heading of 320°. The other ship traveled at a speed of 25 miles per hour at a heading of 197°. Find the distance between the two ships after 10 hours of travel. (Round your answer to the nearest mile.) Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Two ships left a port at the same time. One ship traveled at a speed of 11 miles per hour at a heading of 320°. The other ship traveled at a speed of 25 miles per hour at a heading of 197°. Find the distance between the two ships after 10 hours of travel. (Round your answer to the nearest mile.)
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Given 2 sides and the angle between ---> Cosine Law
Side a = 11*10 = 110 miles
Side b = 25*10 = 250 miles
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The angle between = 320 - 197 = 123 degs
C^2 = a^2 + b^2 - 2ab*cos(123)
You do the calculation.
