SOLUTION: An appliance store sells additional warranties on its refrigerators. twenty percent of the buyers buy the limited warranty for $100 and 5% buy the extended warranty for $200. What

Algebra ->  Probability-and-statistics -> SOLUTION: An appliance store sells additional warranties on its refrigerators. twenty percent of the buyers buy the limited warranty for $100 and 5% buy the extended warranty for $200. What       Log On


   



Question 1204757: An appliance store sells additional warranties on its refrigerators. twenty percent of the buyers buy the limited warranty for $100 and 5% buy the extended warranty for $200. What is the expected revenue for the store from the warranty if it sells 120 refrigerators?
Answer by ikleyn(52834) About Me  (Show Source):
You can put this solution on YOUR website!
.
An appliance store sells additional warranties on its refrigerators.
twenty percent of the buyers buy the limited warranty for $100
and 5% buy the extended warranty for $200.
What is the expected revenue for the store from the warranty if it sells 120 refrigerators?
~~~~~~~~~~~~~~~~~~~~~~~~~

20% of 120 buyers = 24 buyers; they buy the limited warranty of $100.


 5% of 120 buyers = 6 buyers; they buy the extended warranty of $200.


The problem does not tell it explicitly, but from the context, it is clear that the set of those 
who buys the limited warranty and the set of those who buys the extended warranty are disjoint,
i.e. have empty intersection (nobody pays twice).


Therefore, the expected revenue is the sum  24*100 + 6*200 = 3600  dollars.    ANSWER

Solved.