SOLUTION: Find the set of values of x for which
A . 3(2X+1)>5-2x
B.2x*2-7X+3>0
C..BOTH 3(2X+1)>5-2X AND 2X*2-7X+3>0
Algebra ->
Absolute-value
-> SOLUTION: Find the set of values of x for which
A . 3(2X+1)>5-2x
B.2x*2-7X+3>0
C..BOTH 3(2X+1)>5-2X AND 2X*2-7X+3>0
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Question 1204726: Find the set of values of x for which
A . 3(2X+1)>5-2x
B.2x*2-7X+3>0
C..BOTH 3(2X+1)>5-2X AND 2X*2-7X+3>0 Found 2 solutions by Theo, ikleyn:Answer by Theo(13342) (Show Source):
You can put this solution on YOUR website! a.
3 * (2x + 1) > 5 - 2x
simplify to get:
6x + 3 > 5 - 2x
add 2x to both sides and subtract 3 from both sides to get:
8x > 2/8 which becomes x > .25.
b.
2x^2 - 7x + 3 > 0
set it equal to 0 to get:
2x^2 - 7x + 3 = 0
factor to get:
(2x-1) * (x-3) = 0
zero points are x = .5 and x = 3
2x^2 - 7x + 3 is less than zero between x = .5 and x = 3.
it is greater than zero when x is less than .5 and x is greater than 3.
to satisfy both inequalities, you hneed to have both x > .25 and x < .5 and x > 3.
your solution should be .25 < x < .5 or x > 3.
that can be seen in the following graph using desmos.com/calculator.
the area on the graph that is not shaded is your region of feasibility.
