SOLUTION: Find the number of distinguishable permutations of the given letters "AAABBBCD".

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Question 1204716: Find the number of distinguishable permutations of the given letters "AAABBBCD".

Found 2 solutions by MathLover1, ikleyn:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
permutations of { A,+A, A, B, B,+B, C, D }
there are 8 letters
there are 3 As and 3 Bs, since order matters, there will be following number of permutations :

nPr=n%21/(n%5B1%5D%21*n%5B2%5D%21*....*n%5Br%5D%21)

n=8
Distinct subsets:
Subsets : A+=+3; B+=+3; C+=+1; D+=+1;
Subsets' count: n%5B1%5D%28A%29+=+3, n%5B2%5D%28B%29+=+3, n%5B3%5D%28C%29+=+1, n%5B4%5D%28D%29+=+1


The letters of the word AAABBBCD+can be arranged in 1120 distinct ways.


Answer by ikleyn(52921) About Me  (Show Source):
You can put this solution on YOUR website!
.
Find the number of distinguishable permutations of the given letters "AAABBBCD".
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The formula for the number of distinguishable permutations of this word is

    n = 8%21%2F%283%21%2A3%21%29.    (1)


In this formula, 8! reflects the number of all permutations of 8 letters in the word.

First  3!  in the denominator reflects three repeating letters A in it.

Second 3!  in the denominator reflects three repeating letters B in the word.


The  ANSWER  is, according to formula (1),  n = 1120.

Solved.

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To see many other similar  (and different)  solved problems,  look into the lesson
    - Arranging elements of sets containing indistinguishable elements
in this site.

Learn the subject from there.