SOLUTION: Two ships left a port at the same time. One ship traveled at a speed of 11 miles per hour at a heading of 320°. The other ship traveled at a speed of 23 miles per hour at a headin
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-> SOLUTION: Two ships left a port at the same time. One ship traveled at a speed of 11 miles per hour at a heading of 320°. The other ship traveled at a speed of 23 miles per hour at a headin
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Question 1204663: Two ships left a port at the same time. One ship traveled at a speed of 11 miles per hour at a heading of 320°. The other ship traveled at a speed of 23 miles per hour at a heading of 195°. Find the distance between the two ships after 10 hours of travel. (Round your answer to the nearest mile.) Answer by avi2408(1) (Show Source):
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From the diagram, we will use the cosine formula to find the distance between the two ships at 10 hours, i.e., BC.
So, c^2=a^2+b^2-2abcosc
c^2 = 110^2+230^2-2(110)(230)cos125
= 12100+52900+29022.9676=94022.9676.
as c^2 = 94022.9676
c = sqrt(94022.9676) = 306.631 miles, or mi.
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