SOLUTION: Johnnie likes to buy slices of pizza in the cafeteria for lunch for $4.75. Amy prefers to buy hamburgers for lunch, which cost $5.55 each. Between the two of them, Johnnie and Am

Algebra ->  Inequalities -> SOLUTION: Johnnie likes to buy slices of pizza in the cafeteria for lunch for $4.75. Amy prefers to buy hamburgers for lunch, which cost $5.55 each. Between the two of them, Johnnie and Am      Log On


   



Question 1204603: Johnnie likes to buy slices of pizza in the cafeteria for lunch for $4.75. Amy
prefers to buy hamburgers for lunch, which cost $5.55 each. Between the two of
them, Johnnie and Amy have $38.50 and they are not allowed to buy more than
7 lunches. How many hamburgers and slices of pizza can they buy?

Found 2 solutions by josgarithmetic, greenestamps:
Answer by josgarithmetic(39625) About Me  (Show Source):
You can put this solution on YOUR website!
Pizza Slice, 4.75 dollars
Hamburger, 5.55 dollars
Max. money to spend, 38.5 dollars
Max. foods or lunches to buy , 7

p and h, number of pizza slices and hamburgers
system%28p%2Bh%3C=7%2C4.75p%2B5.55h%3C=38.5%29

Understand that p and h must be whole numbers, neither less than 0.

Answer by greenestamps(13203) About Me  (Show Source):
You can put this solution on YOUR website!


No formal algebra is needed for this problem; the requirements are not very restrictive.

Simple arithmetic shows that 7 hamburgers cost $38.85, which is just a bit more than the $38.50 they have to spend.

Then, since hamburgers cost more than slices of pizza....

ANSWER: they can buy ANY combination of 7 or fewer items EXCEPT 7 hamburgers.