SOLUTION: If 129 people attend a concert and tickets for adults cost $2.25 while tickets for children cost $1.5 and total receipts for the concert was $233.25, how many of each went to the c
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Question 1204597: If 129 people attend a concert and tickets for adults cost $2.25 while tickets for children cost $1.5 and total receipts for the concert was $233.25, how many of each went to the concert? Found 3 solutions by ikleyn, josgarithmetic, math_tutor2020:Answer by ikleyn(52775) (Show Source):
You can put this solution on YOUR website! .
If 129 people attend a concert and tickets for adults cost $2.25
while tickets for children cost $1.5 and total receipts for the concert was $233.25,
how many of each went to the concert?
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x adults; (129-x) children
Write the total money equation
2.25x + 1.50*(129-x) = 233.25 dollars.
Simplify and find x
2.25x + 1.50*129 - 1.50x = 233.25
2.25x - 1.50x = 233.25 - 1.50*129
0.75x = 39.75
x = 39.75/0.75 = 53.
ANSWER. 53 adults and 129-53 = 76 children.
CHECK. 53*2.25 + 76*1.50 = 233.25 dollar, total money. ! correct !
That would bring in 2.25*129 = 290.25 dollars in revenue.
This value is to large compared to the actual revenue of $233.25
We need to decrease the revenue by 290.25 - 233.25 = 57 dollars.
We'll need to replace some adults with children to bring the revenue down.
Each time we replace 1 adult with 1 child, the revenue drops by $0.75, aka 75 cents, because 2.25 - 1.50 = 0.75
n = number of times we replace 1 adult with 1 child
0.75n = total decrease in revenue
0.75n = 57
n = 57/0.75
n = 76
We'll have 76 instances where we replace 1 adult with 1 child.
The 129 adults drops to 129-76 = 53 adults.
The 0 children increases to 0+76 = 76 children
Check:
53 adults + 76 children = 129 people total
53 adults bring 53*2.25 = $119.25 in revenue
76 children bring 76*1.5 = $114 in revenue
total revenue = 119.25+114 = 233.25
Or as a shortcut we could say: 53*2.25 + 76*1.5 = 233.25
The answers are confirmed.