Question 1204533: A code of 2 letters and 3 numbers is to be made for a security panel, using A,B,C and 1,2,3,4,5,6. How many codes are possible if repeats are allowed?
Found 2 solutions by Alan3354, ikleyn:
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! A code of 2 letters and 3 numbers is to be made for a security panel, using A,B,C and 1,2,3,4,5,6. How many codes are possible if repeats are allowed?
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3*3*6*6*6 = 1944
Answer by ikleyn(52879)  (Show Source):
You can put this solution on YOUR website! .
The solution by Alan is correct only if positions of letters and digits are fixed:
for example, two letters go first and three digits follow in positions 3, 4 and 5.
But the post does not state it.
If, in opposite, the positions are not fixed (letters and digits can be in any positions),
then this number 3*3*6*6*6 = 1944 from the Alan's post should be multiplied by
 =  = 10, so the final answer is 3*3*6*6*6*10 = 19440.
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