Question 1204453: Shantel has
$
3.60
in dimes and nickles in her car. The number of nickles is three more than the number of dimes. How many of each type of coin does she have?
Found 3 solutions by josgarithmetic, ikleyn, greenestamps:
Answer by josgarithmetic(39630)   (Show Source):
Answer by ikleyn(52894)  (Show Source):
You can put this solution on YOUR website! .
Shantel has $3.60 in dimes and nickles in her car. The number of nickles
is three more than the number of dimes. How many of each type of coin does she have?
~~~~~~~~~~~~~~~~~~~~~
x dimes; (x+3) nickels.
Write the total money equation
10x + 5(x+3) = 360 cents.
Simplify and find x
10x + 5x + 15 = 360
15x = 360 - 15 = 345
x = 345/15 = 23.
ANSWER. 23 dimes and 23+3 = 26 nickels.
CHECK. 23*10 + 26*5 = 360 cents, in total. ! correct !
Solved.
Answer by greenestamps(13209)  (Show Source):
You can put this solution on YOUR website!
Probably a formal algebraic solution, like the one shown by tutor @ikleyn, was wanted. But you can get good mental exercise solving the problem informally, using logical reasoning and mental arithmetic.
The number of nickels is 3 more than the number of dimes, and the total value is $3.60.
Set aside those 3 "extra" nickels, worth $0.15, leaving a value of $3.45 for the remaining coins.
Those remaining coins are equal numbers of nickels and dimes. The value of one nickel and one dime is $0.15. $3.45/$0.15 = 23, so the remaining coins are 23 nickels and 23 dimes.
Now add back in the other 3 nickels, making 26 nickels and 23 dimes.
ANSWER: 26 nickels and 23 dimes
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