SOLUTION: A company finds that it can make a profit of P dollars each month by selling x patterns, according to the formula P(x)=-.002x^2+5.5x-1400. How many patterns must it sell each mon

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Question 1204337: A company finds that it can make a profit of P dollars each month by selling
x patterns, according to the formula
P(x)=-.002x^2+5.5x-1400. How many patterns must it sell each month to have a maximum profit?
To attain maximum profit they must sell
patterns.
What is the maximum profit?
The max profit is $

Answer by ikleyn(52794) About Me  (Show Source):
You can put this solution on YOUR website!
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A company finds that it can make a profit of P dollars each month by selling
x patterns, according to the formula
P(x)=-.002x^2+5.5x-1400. How many patterns must it sell each month to have a maximum profit?
To attain maximum profit they must sell
patterns.
What is the maximum profit?
The max profit is $
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They want you find the maximum of the quadratic function  P(x) = ax^2 + bx + c = -0.002x^2 + 5.5x - 1400.


The general theory says that the maximum is attained at  x%5Bmax%5D = -b%2F%282a%29 = -5.5%2F%282%2A%28-0.002%29%29 = 5.5%2F0.004 = 1375.


To get the value of the maximum profit, substitute this value x%5Bmax%5D = 1375 into the formula for the profit.
You will get

    P%5Bmax%5D = -0.002*1375^2 + 5.5*1375 - 1400 = 2381.25  dollars.


ANSWER.  x%5Bmax%5D = 1375 patterns.

         P%5Bmax%5D = 2381.25  dollars.

Solved.

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On finding the maximum/minimum of a quadratic function see the lessons
    - HOW TO complete the square to find the minimum/maximum of a quadratic function
    - Briefly on finding the minimum/maximum of a quadratic function
    - HOW TO complete the square to find the vertex of a parabola
    - Briefly on finding the vertex of a parabola


Consider these lessons as your textbook,  handbook,  tutorials and  (free of charge)  home teacher.
Learn the subject from there once and for all.