SOLUTION: Hi! May I have some help with this equation? Evaluate the expression and write the result in the form a + bi. 1/(4 - 7i)

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Question 120429: Hi! May I have some help with this equation?
Evaluate the expression and write the result in the form a + bi.
1/(4 - 7i)

Found 2 solutions by jim_thompson5910, bucky:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

Start with the given expression

Multiply the fraction by

Foil and Multiply


Break up the fraction. So it is now in a%2Bbi form where a=4%2F65 and b=7%2F65

Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!
Given:
.
1%2F%284-7i%29
.
You can convert the denominator of this fraction to a real number by multiplying the denominator
by its conjugate ... the same term as the denominator only with the opposite sign between the
terms. In this case, the conjugate is 4%2B7i. If you multiply the denominator by its
conjugate, you must also multiply the numerator by the same conjugate.
.
This multiplication leads to:
.
1%2F%284-7i%29%2A%284%2B7i%29%2F%284%2B7i%29
.
When you multiply the denominators:
.
%284-7i%29%2A%284%2B7i%29
.
You can do so by multiplying the 4 in the first set of parentheses by both terms in the second
set of parentheses and then multiplying the -7i from the first set of parentheses by
both terms in the second set of parentheses:
.
%284-7i%29%2A%284%2B7i%29+=+4%2A4+%2B+4%2A7i+-7i%2A4+-7i%2A7i=+16+%2B+28i+-28i+-49i%5E2
.
Notice that the +28i and the -28i are equal but of opposite sign. Therefore, they cancel
each other out and you are left with:
.
16+-+49i%5E2
.
But, by definition, i%5E2+=+-1. Substitute -1 for i%5E2 and the expression becomes:
.
16-49%28-1%29+=+16%2B49+=+65
.
So the denominator, when multiplied by its conjugate, becomes 65.
.
The numerator, when multiplied by the conjugate, is:
.
1%2A%284%2B7i%29+=+4%2B7i
.
This numerator is then over the denominator 65 to give:
.
%284%2B7i%29%2F65+=+4%2F65+%2B+%287%2F65%29i
.
So the answer to this problem, in the form a + bi, is:
.
4%2F65+%2B%287%2F65%29i
.
Hope this helps you to understand the problem.
.